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What are the solutions to the equation 2x^2-3x=(x-1)(x-1)+(6x^2-5) ?
The solutions to the equation 2x^2-3x=(x-1)(x-1)+(6x^2-5) are x= 4/5 ,x=-1Find the zeros of 2x^2-3x=(x-1)(x-1)+(6x^2-5)
The zeros of 2x^2-3x=(x-1)(x-1)+(6x^2-5) are x= 4/5 ,x=-1