What are the solutions to the equation (x-3)^2=-1 ?

The solutions to the equation (x-3)^2=-1 are x=i+3,x=-i+3

Find the zeros of (x-3)^2=-1

The zeros of (x-3)^2=-1 are x=i+3,x=-i+3

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(x - 3)^{2} = - 1

x = i + 3, x = - i + 3

Solution steps

(x - 3)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 1 : x = i + 3

Solve

x - 3 = - - 1 : x = - i + 3

The solutions to the quadratic equation are:

x = i + 3, x = - i + 3

2 ∣ 5 x + 2 ∣ - 1 = 5

- 35 = 7 t

135 z^{11} - 1080 z^{8}

∣ 8 - 3 x ∣ \leq 11

\frac{7}{12} - \frac{1}{3}

What are the solutions to the equation (x-3)^2=-1 ?
The solutions to the equation (x-3)^2=-1 are x=i+3,x=-i+3
Find the zeros of (x-3)^2=-1
The zeros of (x-3)^2=-1 are x=i+3,x=-i+3