What is factor 49u^2-28u+4 ?

The solution to factor 49u^2-28u+4 is (7u-2)^2

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factor 49u^2-28u+4

factor

49 u^{2} - 28 u + 4

(7 u - 2)^{2}

Solution steps

49 u^{2} - 28 u + 4

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

49 u^{2} = (7 u)^{2}

4 = 2^{2}

- 28 u = - 2 \cdot 7 u \cdot 2

= (7 u)^{2} - 2 \cdot 7 u \cdot 2 + 2^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(7 u)^{2} - 2 \cdot 7 u \cdot 2 + 2^{2} = (7 u - 2)^{2}

= (7 u - 2)^{2}

(\frac{2 x}{y})^{5}

5 x - 5 = 3 x - 9

2 + \frac{3}{4}

2^{0} \cdot 2^{1} \cdot 2^{2} \cdot 2^{3}

3 x^{2} - 4 x + 1