What are the solutions to the equation 3^2+2^2=x^2 ?

The solutions to the equation 3^2+2^2=x^2 are x=sqrt(13),x=-sqrt(13)

Find the zeros of 3^2+2^2=x^2

The zeros of 3^2+2^2=x^2 are x=sqrt(13),x=-sqrt(13)

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3^{2} + 2^{2} = x^{2}

x = 13, x = - 13

Decimal Notation

x = 3.60555 \dots, x = - 3.60555 \dots

Solution steps

3^{2} + 2^{2} = x^{2}

Switch sides

x^{2} = 3^{2} + 2^{2}

Simplify

3^{2} + 2^{2} : 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 13, x = - 13

6 (u + 1) - 10 = 4 (u - 1) + 2 u

3 x^{2} - 19 x - 14

x^{2} + 10 x \geq 24

(X + B)^{3} - X^{3}

(x - 8)^{2} - 9 = 0

What are the solutions to the equation 3^2+2^2=x^2 ?
The solutions to the equation 3^2+2^2=x^2 are x=sqrt(13),x=-sqrt(13)
Find the zeros of 3^2+2^2=x^2
The zeros of 3^2+2^2=x^2 are x=sqrt(13),x=-sqrt(13)