What are the solutions to the equation (x+5)^2=4x^2 ?

The solutions to the equation (x+5)^2=4x^2 are x=-5/3 ,x=5

Find the zeros of (x+5)^2=4x^2

The zeros of (x+5)^2=4x^2 are x=-5/3 ,x=5

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(x + 5)^{2} = 4 x^{2}

x = - \frac{5}{3}, x = 5

Decimal Notation

x = - 1.66666 \dots, x = 5

Solution steps

(x + 5)^{2} = 4 x^{2}

Expand

(x + 5)^{2} : x^{2} + 10 x + 25

x^{2} + 10 x + 25 = 4 x^{2}

Move

4 x^{2}

to the left side

- 3 x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 3 ) \cdot 25}{2 ( - 3 )}

1 0^{2} - 4 (- 3) \cdot 25 = 20

x_{1, 2} = \frac{- 10 \pm 20}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 10 + 20}{2 ( - 3 )}, x_{2} = \frac{- 10 - 20}{2 ( - 3 )}

x = \frac{- 10 + 20}{2 ( - 3 )} : - \frac{5}{3}

x = \frac{- 10 - 20}{2 ( - 3 )} : 5

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = 5

∣ 5 + 2 x ∣ \geq 3

∣ 7 x - 5 ∣ + 5 = 8

\frac{1}{9} (2 m - 16) = \frac{1}{3} (2 m + 4)

(- 6)^{2}

\frac{12}{6}

What are the solutions to the equation (x+5)^2=4x^2 ?
The solutions to the equation (x+5)^2=4x^2 are x=-5/3 ,x=5
Find the zeros of (x+5)^2=4x^2
The zeros of (x+5)^2=4x^2 are x=-5/3 ,x=5