What are the solutions to the equation x^2+11x+61=-4x+5 ?

The solutions to the equation x^2+11x+61=-4x+5 are x=-7,x=-8

Find the zeros of x^2+11x+61=-4x+5

The zeros of x^2+11x+61=-4x+5 are x=-7,x=-8

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x^{2} + 11 x + 61 = - 4 x + 5

x = - 7, x = - 8

Solution steps

x^{2} + 11 x + 61 = - 4 x + 5

Move

5

to the left side

x^{2} + 11 x + 56 = - 4 x

Move

4 x

to the left side

x^{2} + 15 x + 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 56}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 56 = 1

x_{1, 2} = \frac{- 15 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 1}{2 \cdot 1}, x_{2} = \frac{- 15 - 1}{2 \cdot 1}

x = \frac{- 15 + 1}{2 \cdot 1} : - 7

x = \frac{- 15 - 1}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 7, x = - 8

4 x^{2} + 29 x + 7

\frac{1}{\frac{4}{5}}

(\frac{π}{3}) (\frac{180}{π})

81 a^{4} - 64 b^{4}

32 \cdot 6

What are the solutions to the equation x^2+11x+61=-4x+5 ?
The solutions to the equation x^2+11x+61=-4x+5 are x=-7,x=-8
Find the zeros of x^2+11x+61=-4x+5
The zeros of x^2+11x+61=-4x+5 are x=-7,x=-8