What are the solutions to the equation 29x^2-24x-189=0 ?

The solutions to the equation 29x^2-24x-189=0 are x=3,x=-63/29

Find the zeros of 29x^2-24x-189=0

The zeros of 29x^2-24x-189=0 are x=3,x=-63/29

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29 x^{2} - 24 x - 189 = 0

x = 3, x = - \frac{63}{29}

Decimal Notation

x = 3, x = - 2.17241 \dots

Solution steps

29 x^{2} - 24 x - 189 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 29 ( - 189 )}{2 \cdot 29}

(- 24)^{2} - 4 \cdot 29 (- 189) = 150

x_{1, 2} = \frac{- ( - 24 ) \pm 150}{2 \cdot 29}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 150}{2 \cdot 29}, x_{2} = \frac{- ( - 24 ) - 150}{2 \cdot 29}

x = \frac{- ( - 24 ) + 150}{2 \cdot 29} : 3

x = \frac{- ( - 24 ) - 150}{2 \cdot 29} : - \frac{63}{29}

The solutions to the quadratic equation are:

x = 3, x = - \frac{63}{29}

r^{2} - r + 144 = 0

(\frac{1}{25})^{- \frac{3}{2}}

2 x^{2} + 8 x - 4 = 0

\frac{3}{4 ( \frac{1}{4} + 2 ) ^{\frac{5}{2}}}

10 x + 5 < - 8 + 6 x

What are the solutions to the equation 29x^2-24x-189=0 ?
The solutions to the equation 29x^2-24x-189=0 are x=3,x=-63/29
Find the zeros of 29x^2-24x-189=0
The zeros of 29x^2-24x-189=0 are x=3,x=-63/29