What are the solutions to the equation v^2+6v-59=0 ?

The solutions to the equation v^2+6v-59=0 are v=-3+2sqrt(17),v=-3-2sqrt(17)

Find the zeros of v^2+6v-59=0

The zeros of v^2+6v-59=0 are v=-3+2sqrt(17),v=-3-2sqrt(17)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^{2} + 6 v - 59 = 0

v = - 3 + 217, v = - 3 - 217

Decimal Notation

v = 5.24621 \dots, v = - 11.24621 \dots

Solution steps

v^{2} + 6 v - 59 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 59 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 59) = 417

v_{1, 2} = \frac{- 6 \pm 4 17}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 6 + 4 17}{2 \cdot 1}, v_{2} = \frac{- 6 - 4 17}{2 \cdot 1}

v = \frac{- 6 + 4 17}{2 \cdot 1} : - 3 + 217

v = \frac{- 6 - 4 17}{2 \cdot 1} : - 3 - 217

The solutions to the quadratic equation are:

v = - 3 + 217, v = - 3 - 217

lo g_{7} (81)

2 v^{2} - 34 v + 60

5 a - 30

4 - 8

x^{2} + 8 x + 15 < 0

What are the solutions to the equation v^2+6v-59=0 ?
The solutions to the equation v^2+6v-59=0 are v=-3+2sqrt(17),v=-3-2sqrt(17)
Find the zeros of v^2+6v-59=0
The zeros of v^2+6v-59=0 are v=-3+2sqrt(17),v=-3-2sqrt(17)