What is factor n^2+4n-12 ?

The solution to factor n^2+4n-12 is (n-2)(n+6)

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factor n^2+4n-12

factor

n^{2} + 4 n - 12

(n - 2) (n + 6)

Solution steps

n^{2} + 4 n - 12

Break the expression into groups

= (n^{2} - 2 n) + (6 n - 12)

Factor out

n

from

n^{2} - 2 n : n (n - 2)

Factor out

6

from

6 n - 12 : 6 (n - 2)

= n (n - 2) + 6 (n - 2)

Factor out common term

n - 2

= (n - 2) (n + 6)

7 x + 19 = 2 x + 55

x^{2} - 54 x - 50 = 0

n^{2} + 4 n + 72 = 0

∣ 9 - 2 x ∣ > 5

2 x + 10 < 22