What is the answer to sqrt(|x^2+12x+6|-5)=|x+6|+1 ?

The answer to sqrt(|x^2+12x+6|-5)=|x+6|+1 is x=-9\lor x=-3

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sqrt(|x^2+12x+6|-5)=|x+6|+1

∣ x^{2} + 12 x + 6 ∣ - 5 = ∣ x + 6 ∣ + 1

x = - 9 or x = - 3

Solution steps

∣ x^{2} + 12 x + 6 ∣ - 5 = ∣ x + 6 ∣ + 1

Find positive and negative intervals

x \leq - 30 - 6, - 30 - 6 < x < - 6, - 6 \leq x < 30 - 6, x \geq 30 - 6

Solve the inequality for each interval

No Solution or x = - 9 or x = - 3

x = - 9 or x = - 3

e^{- 7}

3 j - (5 j - 11) < 4 (15 - 3 j) + 9

\frac{5 x ^{6} y ^{8}}{125 x y}

15 (t + 2) + 9 t = 6

\frac{2}{5} \cdot \frac{7}{9}

What is the answer to sqrt(|x^2+12x+6|-5)=|x+6|+1 ?
The answer to sqrt(|x^2+12x+6|-5)=|x+6|+1 is x=-9\lor x=-3
Solve for x: sqrt(|x^2+12x+6|-5)=|x+6|+1
The solution is x=-9\lor x=-3