What are the solutions to the equation 2x^2+5x-6=0 ?

The solutions to the equation 2x^2+5x-6=0 are x=(-5+sqrt(73))/4 ,x=(-5-sqrt(73))/4

Find the zeros of 2x^2+5x-6=0

The zeros of 2x^2+5x-6=0 are x=(-5+sqrt(73))/4 ,x=(-5-sqrt(73))/4

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2 x^{2} + 5 x - 6 = 0

x = \frac{- 5 + 73}{4}, x = \frac{- 5 - 73}{4}

Decimal Notation

x = 0.88600 \dots, x = - 3.38600 \dots

Solution steps

2 x^{2} + 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 6) = 73

x_{1, 2} = \frac{- 5 \pm 73}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 73}{2 \cdot 2}, x_{2} = \frac{- 5 - 73}{2 \cdot 2}

x = \frac{- 5 + 73}{2 \cdot 2} : \frac{- 5 + 73}{4}

x = \frac{- 5 - 73}{2 \cdot 2} : \frac{- 5 - 73}{4}

The solutions to the quadratic equation are:

x = \frac{- 5 + 73}{4}, x = \frac{- 5 - 73}{4}

\frac{( 500 \cdot 1 2 ^{2} )}{12}

15 x - 7 = 23 x - 79

x^{3} + 8

∣ 6 x + 3 ∣ = 6

What are the solutions to the equation 2x^2+5x-6=0 ?
The solutions to the equation 2x^2+5x-6=0 are x=(-5+sqrt(73))/4 ,x=(-5-sqrt(73))/4
Find the zeros of 2x^2+5x-6=0
The zeros of 2x^2+5x-6=0 are x=(-5+sqrt(73))/4 ,x=(-5-sqrt(73))/4