What are the solutions to the equation v^2+9v+20=0 ?

The solutions to the equation v^2+9v+20=0 are v=-4,v=-5

Find the zeros of v^2+9v+20=0

The zeros of v^2+9v+20=0 are v=-4,v=-5

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v^{2} + 9 v + 20 = 0

v = - 4, v = - 5

Solution steps

v^{2} + 9 v + 20 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

v_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 9 + 1}{2 \cdot 1}, v_{2} = \frac{- 9 - 1}{2 \cdot 1}

v = \frac{- 9 + 1}{2 \cdot 1} : - 4

v = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

v = - 4, v = - 5

\frac{4}{9} x^{2} y^{2} - \frac{25}{36} z^{2}

12 x^{2} - 2 x - 5 = 4 x^{2} - 8 x

(- \frac{2}{3})^{- 3}

x^{2} - 20 x + 75 = 0

i^{347}

What are the solutions to the equation v^2+9v+20=0 ?
The solutions to the equation v^2+9v+20=0 are v=-4,v=-5
Find the zeros of v^2+9v+20=0
The zeros of v^2+9v+20=0 are v=-4,v=-5