What are the solutions to the equation 18x^2-6x+1=0 ?

The solutions to the equation 18x^2-6x+1=0 are x= 1/6+i 1/6 ,x= 1/6-i 1/6

Find the zeros of 18x^2-6x+1=0

The zeros of 18x^2-6x+1=0 are x= 1/6+i 1/6 ,x= 1/6-i 1/6

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18 x^{2} - 6 x + 1 = 0

x = \frac{1}{6} + i \frac{1}{6}, x = \frac{1}{6} - i \frac{1}{6}

Solution steps

18 x^{2} - 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 18 \cdot 1}{2 \cdot 18}

Simplify

(- 6)^{2} - 4 \cdot 18 \cdot 1 : 6 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 i}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 i}{2 \cdot 18}, x_{2} = \frac{- ( - 6 ) - 6 i}{2 \cdot 18}

x = \frac{- ( - 6 ) + 6 i}{2 \cdot 18} : \frac{1}{6} + i \frac{1}{6}

x = \frac{- ( - 6 ) - 6 i}{2 \cdot 18} : \frac{1}{6} - i \frac{1}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{1}{6}, x = \frac{1}{6} - i \frac{1}{6}

5 + \frac{3}{2}

2 x^{2} - 7 x - 5 = 0

\frac{3 ( x + 1 )}{6} = 2 x - 1

5 (x + 8) = 40

2 x - 4 = - 10

What are the solutions to the equation 18x^2-6x+1=0 ?
The solutions to the equation 18x^2-6x+1=0 are x= 1/6+i 1/6 ,x= 1/6-i 1/6
Find the zeros of 18x^2-6x+1=0
The zeros of 18x^2-6x+1=0 are x= 1/6+i 1/6 ,x= 1/6-i 1/6