What is (|x+6|)/8 <= 1 ?

The solution to (|x+6|)/8 <= 1 is -14<= x<= 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(|x+6|)/8 <= 1

\frac{∣ x + 6 ∣}{8} \leq 1

- 14 \leq x \leq 2

Interval Notation

[- 14, 2]

Solution steps

\frac{∣ x + 6 ∣}{8} \leq 1

Multiply both sides by

8

∣ x + 6 ∣ \leq 8

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 8 \leq x + 6 \leq 8

x + 6 \geq - 8 and x + 6 \leq 8

x \geq - 14 and x \leq 2

Merge Overlapping Intervals

- 14 \leq x \leq 2

6 y^{2} - 24 y = 0

2 x^{2} - 3 x + 7 = 0

x + 2 = 2 x - 3

\frac{2}{1 - \frac{1}{3}}

\frac{7 + x}{7 - x} \geq 1