What are the solutions to the equation 12x^2+4x-5=0 ?

The solutions to the equation 12x^2+4x-5=0 are x= 1/2 ,x=-5/6

Find the zeros of 12x^2+4x-5=0

The zeros of 12x^2+4x-5=0 are x= 1/2 ,x=-5/6

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12 x^{2} + 4 x - 5 = 0

x = \frac{1}{2}, x = - \frac{5}{6}

Decimal Notation

x = 0.5, x = - 0.83333 \dots

Solution steps

12 x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 12 ( - 5 )}{2 \cdot 12}

4^{2} - 4 \cdot 12 (- 5) = 16

x_{1, 2} = \frac{- 4 \pm 16}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 4 + 16}{2 \cdot 12}, x_{2} = \frac{- 4 - 16}{2 \cdot 12}

x = \frac{- 4 + 16}{2 \cdot 12} : \frac{1}{2}

x = \frac{- 4 - 16}{2 \cdot 12} : - \frac{5}{6}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{5}{6}

- 16 t^{2} + 40 t + 5 = 0

\frac{6 - 2}{- 3 + 2}

\frac{1}{x} + h

17 \leq \frac{x}{2} + 11

8 + 63

What are the solutions to the equation 12x^2+4x-5=0 ?
The solutions to the equation 12x^2+4x-5=0 are x= 1/2 ,x=-5/6
Find the zeros of 12x^2+4x-5=0
The zeros of 12x^2+4x-5=0 are x= 1/2 ,x=-5/6