What is 8x+1>-5\land 4x+1<= 17 ?

The solution to 8x+1>-5\land 4x+1<= 17 is -3/4 <x<= 4

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8x+1>-5\land 4x+1<= 17

8 x + 1 > - 5 and 4 x + 1 \leq 17

- \frac{3}{4} < x \leq 4

Interval Notation

(- \frac{3}{4}, 4]

Decimal Notation

- 0.75 < x \leq 4

Solution steps

8 x + 1 > - 5 and 4 x + 1 \leq 17

8 x + 1 > - 5 : x > - \frac{3}{4}

4 x + 1 \leq 17 : x \leq 4

Combine the intervals

x > - \frac{3}{4} and x \leq 4

Merge Overlapping Intervals

- \frac{3}{4} < x \leq 4

\frac{x - 2}{x ^{2} - 9} < 0

6^{6}

\frac{2 a ^{7}}{6 a ^{9}}

16 < x < 81

3 x - 2 < 1 or 5 - 2 x \geq - 7

What is 8x+1>-5\land 4x+1<= 17 ?
The solution to 8x+1>-5\land 4x+1<= 17 is -3/4 <x<= 4