What are the solutions to the equation x^2+12x+3=7 ?

The solutions to the equation x^2+12x+3=7 are x=2(sqrt(10)-3),x=-2(3+sqrt(10))

Find the zeros of x^2+12x+3=7

The zeros of x^2+12x+3=7 are x=2(sqrt(10)-3),x=-2(3+sqrt(10))

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x^{2} + 12 x + 3 = 7

x = 2 (10 - 3), x = - 2 (3 + 10)

Decimal Notation

x = 0.32455 \dots, x = - 12.32455 \dots

Solution steps

x^{2} + 12 x + 3 = 7

Move

7

to the left side

x^{2} + 12 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 4) = 410

x_{1, 2} = \frac{- 12 \pm 4 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 4 10}{2 \cdot 1}, x_{2} = \frac{- 12 - 4 10}{2 \cdot 1}

x = \frac{- 12 + 4 10}{2 \cdot 1} : 2 (10 - 3)

x = \frac{- 12 - 4 10}{2 \cdot 1} : - 2 (3 + 10)

The solutions to the quadratic equation are:

x = 2 (10 - 3), x = - 2 (3 + 10)

7 x + 5 \leq - 9

- 6 - 2 y^{2} + 6 x - 4 x + 1 + 7 y^{2} - y^{2}

4 x - 12 \geq 8 x + 4

\frac{x + 4}{7} = \frac{3}{7}

\frac{4}{3} (2 x - 3) < 5 - 2 x

What are the solutions to the equation x^2+12x+3=7 ?
The solutions to the equation x^2+12x+3=7 are x=2(sqrt(10)-3),x=-2(3+sqrt(10))
Find the zeros of x^2+12x+3=7
The zeros of x^2+12x+3=7 are x=2(sqrt(10)-3),x=-2(3+sqrt(10))