What are the solutions to the equation x^2-12x=-20 ?

The solutions to the equation x^2-12x=-20 are x=10,x=2

Find the zeros of x^2-12x=-20

The zeros of x^2-12x=-20 are x=10,x=2

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x^{2} - 12 x = - 20

x = 10, x = 2

Solution steps

x^{2} - 12 x = - 20

Move

20

to the left side

x^{2} - 12 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 20 = 8

x_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 1}

x = \frac{- ( - 12 ) + 8}{2 \cdot 1} : 10

x = \frac{- ( - 12 ) - 8}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 10, x = 2

\frac{5}{6} x - 3 x + \frac{4}{3} = \frac{5}{3}

∣ 2 - x ∣ \leq \frac{3}{7}

ln (0.9)

5 x^{2} + 17 x - 12

- 9 x > 54

What are the solutions to the equation x^2-12x=-20 ?
The solutions to the equation x^2-12x=-20 are x=10,x=2
Find the zeros of x^2-12x=-20
The zeros of x^2-12x=-20 are x=10,x=2