What are the solutions to the equation m^2-2m+4=0 ?

The solutions to the equation m^2-2m+4=0 are m=1+sqrt(3)i,m=1-sqrt(3)i

Find the zeros of m^2-2m+4=0

The zeros of m^2-2m+4=0 are m=1+sqrt(3)i,m=1-sqrt(3)i

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m^{2} - 2 m + 4 = 0

m = 1 + 3 i, m = 1 - 3 i

Solution steps

m^{2} - 2 m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 4 : 23 i

m_{1, 2} = \frac{- ( - 2 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1}

m = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1} : 1 + 3 i

m = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

m = 1 + 3 i, m = 1 - 3 i

2 x^{2} + 12 x + 16

125 x^{3} + 8

(\frac{1}{x}) - (\frac{3}{( x - 2 )}) \leq 1

\frac{1}{7} \cdot 3

\frac{10 + 40 i}{- 3 + 5 i}

What are the solutions to the equation m^2-2m+4=0 ?
The solutions to the equation m^2-2m+4=0 are m=1+sqrt(3)i,m=1-sqrt(3)i
Find the zeros of m^2-2m+4=0
The zeros of m^2-2m+4=0 are m=1+sqrt(3)i,m=1-sqrt(3)i