What is factor 21n^2+8n-4 ?

The solution to factor 21n^2+8n-4 is (7n-2)(3n+2)

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factor 21n^2+8n-4

factor

21 n^{2} + 8 n - 4

(7 n - 2) (3 n + 2)

Solution steps

21 n^{2} + 8 n - 4

Break the expression into groups

= (21 n^{2} - 6 n) + (14 n - 4)

Factor out

3 n

from

21 n^{2} - 6 n : 3 n (7 n - 2)

Factor out

2

from

14 n - 4 : 2 (7 n - 2)

= 3 n (7 n - 2) + 2 (7 n - 2)

Factor out common term

7 n - 2

= (7 n - 2) (3 n + 2)

- 9 x + 2 > 18 and 13 x + 15 \leq - 4

3 b^{2} - 10 b + 3

\frac{( \frac{3}{2} )}{( \frac{1}{2} )}

6 r - 1 + 6 r = 11

\frac{x ^{- 5} + y ^{- 4}}{x ^{- 4} + y ^{- 3}}