What are the solutions to the equation d^2+4d+4=0 ?

The solutions to the equation d^2+4d+4=0 are d=-2

Find the zeros of d^2+4d+4=0

The zeros of d^2+4d+4=0 are d=-2

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d^{2} + 4 d + 4 = 0

d = - 2

Solution steps

d^{2} + 4 d + 4 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

d_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

d = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

d = - 2

The solution to the quadratic equation is:

d = - 2

x^{2} - 2 x - 15 = 0

\frac{x + 2}{3} - \frac{2 - x}{6} = x - 2

- 4 c^{4} + 8 c^{3} - 28 c^{2}

9 a^{6} b^{- 4}

- \frac{1}{3} (2)

What are the solutions to the equation d^2+4d+4=0 ?
The solutions to the equation d^2+4d+4=0 are d=-2
Find the zeros of d^2+4d+4=0
The zeros of d^2+4d+4=0 are d=-2