What is (5a^4)/(-2(a^4m^{-4))^{-1}} ?

The solution to (5a^4)/(-2(a^4m^{-4))^{-1}} is -(5a^8)/(2m^4)

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simplify (5a^4)/(-2(a^4m^{-4))^{-1}}

simplify

\frac{5 a ^{4}}{- 2 ( a ^{4} m ^{- 4} ) ^{- 1}}

- \frac{5 a ^{8}}{2 m ^{4}}

Solution steps

\frac{5 a ^{4}}{- 2 ( a ^{4} m ^{- 4} ) ^{- 1}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{5 a ^{4}}{2 ( a ^{4} m ^{- 4} ) ^{- 1}}

Simplify

2 (a^{4} m^{- 4})^{- 1} : \frac{2 m ^{4}}{a ^{4}}

= - \frac{5 a ^{4}}{\frac{2 m ^{4}}{a ^{4}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

\frac{5 a ^{4}}{\frac{2 m ^{4}}{a ^{4}}} = \frac{5 a ^{4} a ^{4}}{2 m ^{4}}

= - \frac{5 a ^{4} a ^{4}}{2 m ^{4}}

Simplify

a^{4} a^{4} : a^{8}

= - \frac{5 a ^{8}}{2 m ^{4}}

7 x \leq 7 (x - 6)

- \frac{7}{6} - (- \frac{1}{4})

x^{\frac{1}{2}} \cdot \frac{1}{2} x^{- \frac{1}{2}}

8 x + 9 = 6 x + 27

\frac{1}{11} ∣ 2 x - 4 ∣ + 10 \leq 11

What is (5a^4)/(-2(a^4m^{-4))^{-1}} ?
The solution to (5a^4)/(-2(a^4m^{-4))^{-1}} is -(5a^8)/(2m^4)