What are the solutions to the equation 12^2+5^2=x^2 ?

The solutions to the equation 12^2+5^2=x^2 are x=13,x=-13

Find the zeros of 12^2+5^2=x^2

The zeros of 12^2+5^2=x^2 are x=13,x=-13

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1 2^{2} + 5^{2} = x^{2}

x = 13, x = - 13

Solution steps

1 2^{2} + 5^{2} = x^{2}

Switch sides

x^{2} = 1 2^{2} + 5^{2}

Simplify

1 2^{2} + 5^{2} : 169

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 169, x = - 169

169 = 13

- 169 = - 13

x = 13, x = - 13

0.25 x = 0.2 x + 15

32 a^{2} - 50 b^{2}

(- \frac{3}{4} p)^{3}

5 x^{3} - 5 x^{2} + 5 x - 5

\frac{w ^{- 5}}{w ^{- 8}}

What are the solutions to the equation 12^2+5^2=x^2 ?
The solutions to the equation 12^2+5^2=x^2 are x=13,x=-13
Find the zeros of 12^2+5^2=x^2
The zeros of 12^2+5^2=x^2 are x=13,x=-13