What are the solutions to the equation 2x^2+20x+44=0 ?

The solutions to the equation 2x^2+20x+44=0 are x=-5+sqrt(3),x=-5-sqrt(3)

Find the zeros of 2x^2+20x+44=0

The zeros of 2x^2+20x+44=0 are x=-5+sqrt(3),x=-5-sqrt(3)

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2 x^{2} + 20 x + 44 = 0

x = - 5 + 3, x = - 5 - 3

Decimal Notation

x = - 3.26794 \dots, x = - 6.73205 \dots

Solution steps

2 x^{2} + 20 x + 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 44}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 \cdot 44 = 43

x_{1, 2} = \frac{- 20 \pm 4 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 4 3}{2 \cdot 2}, x_{2} = \frac{- 20 - 4 3}{2 \cdot 2}

x = \frac{- 20 + 4 3}{2 \cdot 2} : - 5 + 3

x = \frac{- 20 - 4 3}{2 \cdot 2} : - 5 - 3

The solutions to the quadratic equation are:

x = - 5 + 3, x = - 5 - 3

a^{3} + a^{2} + a + 1

x^{2} - 5 y + 5 x - x y

\frac{3}{2 + 3}

4 x - 2 = - 14 + 4 (2 x - 1)

x = 2 x + 8

What are the solutions to the equation 2x^2+20x+44=0 ?
The solutions to the equation 2x^2+20x+44=0 are x=-5+sqrt(3),x=-5-sqrt(3)
Find the zeros of 2x^2+20x+44=0
The zeros of 2x^2+20x+44=0 are x=-5+sqrt(3),x=-5-sqrt(3)