What are the solutions to the equation 3^2+b^2=8^2 ?

The solutions to the equation 3^2+b^2=8^2 are b=sqrt(55),b=-sqrt(55)

Find the zeros of 3^2+b^2=8^2

The zeros of 3^2+b^2=8^2 are b=sqrt(55),b=-sqrt(55)

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3^{2} + b^{2} = 8^{2}

b = 55, b = - 55

Decimal Notation

b = 7.41619 \dots, b = - 7.41619 \dots

Solution steps

3^{2} + b^{2} = 8^{2}

Move

3^{2}

to the right side

b^{2} = 55

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 55, b = - 55

5 ∣ x - 3 ∣ + 6 < 51

x^{2} + x (- \frac{x}{2}) - (\frac{x}{2})^{2}

6 x y - 4 y

x^{2} - 7 x - 24 = 0

0 = x^{2} + 2 \cdot 29.1732477 \cdot 32

What are the solutions to the equation 3^2+b^2=8^2 ?
The solutions to the equation 3^2+b^2=8^2 are b=sqrt(55),b=-sqrt(55)
Find the zeros of 3^2+b^2=8^2
The zeros of 3^2+b^2=8^2 are b=sqrt(55),b=-sqrt(55)