What is factor 21bc^2-6c-3c^3+42b ?

The solution to factor 21bc^2-6c-3c^3+42b is 3(c^2+2)(7b-c)

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factor 21bc^2-6c-3c^3+42b

factor

21 b c^{2} - 6 c - 3 c^{3} + 42 b

3 (c^{2} + 2) (7 b - c)

Solution steps

21 b c^{2} - 6 c - 3 c^{3} + 42 b

Factor out common term

3 : 3 (7 b c^{2} - 2 c - c^{3} + 14 b)

= 3 (7 b c^{2} - 2 c - c^{3} + 14 b)

Factor

7 b c^{2} - 2 c - c^{3} + 14 b : (c^{2} + 2) (7 b - c)

= 3 (c^{2} + 2) (7 b - c)

\frac{1}{2} + \frac{1}{7}

5 x^{2} - 3 x \geq 8

8 - (- 4)

4 (\frac{81}{17})

(27)^{\frac{2}{3}}

What is factor 21bc^2-6c-3c^3+42b ?
The solution to factor 21bc^2-6c-3c^3+42b is 3(c^2+2)(7b-c)