What are the solutions to the equation x^2+4x-44=0 ?

The solutions to the equation x^2+4x-44=0 are x=2(2sqrt(3)-1),x=-2(1+2sqrt(3))

Find the zeros of x^2+4x-44=0

The zeros of x^2+4x-44=0 are x=2(2sqrt(3)-1),x=-2(1+2sqrt(3))

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x^{2} + 4 x - 44 = 0

x = 2 (23 - 1), x = - 2 (1 + 23)

Decimal Notation

x = 4.92820 \dots, x = - 8.92820 \dots

Solution steps

x^{2} + 4 x - 44 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 44 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 44) = 83

x_{1, 2} = \frac{- 4 \pm 8 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 8 3}{2 \cdot 1}, x_{2} = \frac{- 4 - 8 3}{2 \cdot 1}

x = \frac{- 4 + 8 3}{2 \cdot 1} : 2 (23 - 1)

x = \frac{- 4 - 8 3}{2 \cdot 1} : - 2 (1 + 23)

The solutions to the quadratic equation are:

x = 2 (23 - 1), x = - 2 (1 + 23)

5 + 5

lo g_{18} (1)

\frac{6}{5} x + \frac{1}{3} > \frac{4}{3}

3 x - 1 \geq 3 + x

- 4 + 2 i

What are the solutions to the equation x^2+4x-44=0 ?
The solutions to the equation x^2+4x-44=0 are x=2(2sqrt(3)-1),x=-2(1+2sqrt(3))
Find the zeros of x^2+4x-44=0
The zeros of x^2+4x-44=0 are x=2(2sqrt(3)-1),x=-2(1+2sqrt(3))