What is factor 3x^4-2x^3+11x^2-8x-4 ?

The solution to factor 3x^4-2x^3+11x^2-8x-4 is (x-1)(3x+1)(x^2+4)

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factor 3x^4-2x^3+11x^2-8x-4

factor

3 x^{4} - 2 x^{3} + 11 x^{2} - 8 x - 4

(x - 1) (3 x + 1) (x^{2} + 4)

Solution steps

3 x^{4} - 2 x^{3} + 11 x^{2} - 8 x - 4

Use the rational root theorem

= (x - 1) \frac{3 x ^{4} - 2 x ^{3} + 11 x ^{2} - 8 x - 4}{x - 1}

\frac{3 x ^{4} - 2 x ^{3} + 11 x ^{2} - 8 x - 4}{x - 1} = 3 x^{3} + x^{2} + 12 x + 4

= (x - 1) (3 x^{3} + x^{2} + 12 x + 4)

Factor

3 x^{3} + x^{2} + 12 x + 4 : (3 x + 1) (x^{2} + 4)

= (x - 1) (3 x + 1) (x^{2} + 4)

(x + 2 i)^{2} (x - 2 i)^{2}

\frac{2 a ^{2} b}{b ^{2} c} \cdot \frac{b}{a}

x^{3} y^{3} + 64

\frac{\frac{3 π}{4}}{2}

lo g_{2} (2^{3})

What is factor 3x^4-2x^3+11x^2-8x-4 ?
The solution to factor 3x^4-2x^3+11x^2-8x-4 is (x-1)(3x+1)(x^2+4)