What is (3/4)^2-1/4-(-3/8)^2+(1/4)^3 ?

The solution to (3/4)^2-1/4-(-3/8)^2+(1/4)^3 is 3/16

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simplify (3/4)^2-1/4-(-3/8)^2+(1/4)^3

simplify

(\frac{3}{4})^{2} - \frac{1}{4} - (- \frac{3}{8})^{2} + (\frac{1}{4})^{3}

\frac{3}{16}

Decimal Notation

0.1875

Solution steps

(\frac{3}{4})^{2} - \frac{1}{4} - (- \frac{3}{8})^{2} + (\frac{1}{4})^{3}

(\frac{3}{4})^{2} = \frac{9}{16}

(- \frac{3}{8})^{2} = \frac{9}{64}

(\frac{1}{4})^{3} = \frac{1}{64}

= \frac{9}{16} - \frac{1}{4} - \frac{9}{64} + \frac{1}{64}

\frac{9}{16} - \frac{1}{4} - \frac{9}{64} + \frac{1}{64} = \frac{3}{16}

= \frac{3}{16}

\frac{1}{t 1 + t} - \frac{1}{t}

6 v + 2 = 9 v + 14

\frac{20 - 40 ( 1 )}{1 ^{2}} + \frac{1}{2}

(32 x^{2})^{\frac{6}{5}}

\frac{216}{6}

What is (3/4)^2-1/4-(-3/8)^2+(1/4)^3 ?
The solution to (3/4)^2-1/4-(-3/8)^2+(1/4)^3 is 3/16