What are the solutions to the equation x^2-7x-25=0 ?

The solutions to the equation x^2-7x-25=0 are x=(7+sqrt(149))/2 ,x=(7-sqrt(149))/2

Find the zeros of x^2-7x-25=0

The zeros of x^2-7x-25=0 are x=(7+sqrt(149))/2 ,x=(7-sqrt(149))/2

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x^{2} - 7 x - 25 = 0

x = \frac{7 + 149}{2}, x = \frac{7 - 149}{2}

Decimal Notation

x = 9.60327 \dots, x = - 2.60327 \dots

Solution steps

x^{2} - 7 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 25) = 149

x_{1, 2} = \frac{- ( - 7 ) \pm 149}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 149}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 149}{2 \cdot 1}

x = \frac{- ( - 7 ) + 149}{2 \cdot 1} : \frac{7 + 149}{2}

x = \frac{- ( - 7 ) - 149}{2 \cdot 1} : \frac{7 - 149}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 149}{2}, x = \frac{7 - 149}{2}

2 - 3 x < - 14

\frac{3 - 5 i}{7 + 2 i}

\frac{245 m ^{3} n}{320 m ^{3} n ^{5}}

\frac{100}{1} = \frac{x}{\frac{3}{2}} \cdot 5466313

\frac{14}{7 ^{\frac{2}{3}}}

What are the solutions to the equation x^2-7x-25=0 ?
The solutions to the equation x^2-7x-25=0 are x=(7+sqrt(149))/2 ,x=(7-sqrt(149))/2
Find the zeros of x^2-7x-25=0
The zeros of x^2-7x-25=0 are x=(7+sqrt(149))/2 ,x=(7-sqrt(149))/2