What are the solutions to the equation -3x^2-6x+4=0 ?

The solutions to the equation -3x^2-6x+4=0 are x=-(3+sqrt(21))/3 ,x=(sqrt(21)-3)/3

Find the zeros of -3x^2-6x+4=0

The zeros of -3x^2-6x+4=0 are x=-(3+sqrt(21))/3 ,x=(sqrt(21)-3)/3

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- 3 x^{2} - 6 x + 4 = 0

x = - \frac{3 + 21}{3}, x = \frac{21 - 3}{3}

Decimal Notation

x = - 2.52752 \dots, x = 0.52752 \dots

Solution steps

- 3 x^{2} - 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 3 ) \cdot 4}{2 ( - 3 )}

(- 6)^{2} - 4 (- 3) \cdot 4 = 221

x_{1, 2} = \frac{- ( - 6 ) \pm 2 21}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 21}{2 ( - 3 )}, x_{2} = \frac{- ( - 6 ) - 2 21}{2 ( - 3 )}

x = \frac{- ( - 6 ) + 2 21}{2 ( - 3 )} : - \frac{3 + 21}{3}

x = \frac{- ( - 6 ) - 2 21}{2 ( - 3 )} : \frac{21 - 3}{3}

The solutions to the quadratic equation are:

x = - \frac{3 + 21}{3}, x = \frac{21 - 3}{3}

\frac{1}{2} 4

\frac{1}{2}

\frac{30 a ^{5} \times a ^{3}}{12 a}

100 m^{8} - 9

x^{2} = (x - 2)^{2} + (x - 4)^{2}

What are the solutions to the equation -3x^2-6x+4=0 ?
The solutions to the equation -3x^2-6x+4=0 are x=-(3+sqrt(21))/3 ,x=(sqrt(21)-3)/3
Find the zeros of -3x^2-6x+4=0
The zeros of -3x^2-6x+4=0 are x=-(3+sqrt(21))/3 ,x=(sqrt(21)-3)/3