What are the solutions to the equation x^2-2x-35=0 ?

The solutions to the equation x^2-2x-35=0 are x=7,x=-5

Find the zeros of x^2-2x-35=0

The zeros of x^2-2x-35=0 are x=7,x=-5

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x^{2} - 2 x - 35 = 0

x = 7, x = - 5

Solution steps

x^{2} - 2 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 35) = 12

x_{1, 2} = \frac{- ( - 2 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 12}{2 \cdot 1}

x = \frac{- ( - 2 ) + 12}{2 \cdot 1} : 7

x = \frac{- ( - 2 ) - 12}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 7, x = - 5

3 x^{2} - 54 x + 819 = 0

r^{5} - 6 = - 1

\frac{3}{4} \cdot \frac{2}{5}

\frac{3}{2} (\frac{π}{2} + \frac{3 π}{2})

∣ 5 - 7 ∣

What are the solutions to the equation x^2-2x-35=0 ?
The solutions to the equation x^2-2x-35=0 are x=7,x=-5
Find the zeros of x^2-2x-35=0
The zeros of x^2-2x-35=0 are x=7,x=-5