What is the answer to 4(4-6t)+(1+9t)+2(2+3t)=1 ?

The answer to 4(4-6t)+(1+9t)+2(2+3t)=1 is t= 20/9

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4(4-6t)+(1+9t)+2(2+3t)=1

4 (4 - 6 t) + (1 + 9 t) + 2 (2 + 3 t) = 1

t = \frac{20}{9}

Decimal Notation

t = 2.22222 \dots

Solution steps

4 (4 - 6 t) + (1 + 9 t) + 2 (2 + 3 t) = 1

4 (4 - 6 t) + 1 + 9 t + 2 (2 + 3 t) = 1

Move

1

to the right side

4 (4 - 6 t) + 9 t + 2 (2 + 3 t) = 0

Expand

4 (4 - 6 t) + 9 t + 2 (2 + 3 t) : - 9 t + 20

- 9 t + 20 = 0

Move

20

to the right side

- 9 t = - 20

Divide both sides by

- 9

t = \frac{20}{9}

4 (\frac{2}{3})

w^{2} + 14 w + 49

\frac{5 x - 2}{3} - \frac{x - 8}{4} > \frac{x + 14}{2} - 2

5 - \frac{5}{3}

\frac{1 0 ^{6}}{1 0 ^{4}}

What is the answer to 4(4-6t)+(1+9t)+2(2+3t)=1 ?
The answer to 4(4-6t)+(1+9t)+2(2+3t)=1 is t= 20/9
Solve for t: 4(4-6t)+(1+9t)+2(2+3t)=1
The solution is t= 20/9