What is (4n^2}{3m^2}*\frac{9m)/2 ?

The solution to (4n^2}{3m^2}*\frac{9m)/2 is (6n^2)/m

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (4n^2}{3m^2}*\frac{9m)/2

simplify

\frac{4 n ^{2}}{3 m ^{2}} \cdot \frac{9 m}{2}

\frac{6 n ^{2}}{m}

Solution steps

\frac{4 n ^{2}}{3 m ^{2}} \cdot \frac{9 m}{2}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 n ^{2} \cdot 9 m}{3 m ^{2} \cdot 2}

Factor the number:

4 = 2 \cdot 2

= \frac{2 \cdot 2 n ^{2} \cdot 9 m}{3 m ^{2} \cdot 2}

Cancel the common factor:

2

= \frac{2 n ^{2} \cdot 9 m}{3 m ^{2}}

Factor the number:

9 = 3 \cdot 3

= \frac{2 n ^{2} \cdot 3 \cdot 3 m}{3 m ^{2}}

Cancel the common factor:

3

= \frac{2 n ^{2} \cdot 3 m}{m ^{2}}

Simplify

\frac{m}{m ^{2}} : \frac{1}{m}

= \frac{2 n ^{2} \cdot 3}{m}

Multiply the numbers:

2 \cdot 3 = 6

= \frac{6 n ^{2}}{m}

3 x^{2} = 2 x + 12

a^{2} + 12 = 7 a

h^{2} = 169

0 = - x^{2} + 2 x

(- 128)^{\frac{3}{7}}

What is (4n^2}{3m^2}*\frac{9m)/2 ?
The solution to (4n^2}{3m^2}*\frac{9m)/2 is (6n^2)/m