What are the solutions to the equation 4=m^3+3 ?

The solutions to the equation 4=m^3+3 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i

Find the zeros of 4=m^3+3

The zeros of 4=m^3+3 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i

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4 = m^{3} + 3

m = 1, m = - \frac{1}{2} + \frac{3}{2} i, m = - \frac{1}{2} - \frac{3}{2} i

Solution steps

4 = m^{3} + 3

Switch sides

m^{3} + 3 = 4

Move

3

to the right side

m^{3} = 1

For

x^{3} = f (a)

the solutions are

m = 1, m = \frac{- 1 + 3 i}{2}, m = \frac{- 1 - 3 i}{2}

Simplify

\frac{- 1 + 3 i}{2} : - \frac{1}{2} + \frac{3}{2} i

Simplify

\frac{- 1 - 3 i}{2} : - \frac{1}{2} - \frac{3}{2} i

m = 1, m = - \frac{1}{2} + \frac{3}{2} i, m = - \frac{1}{2} - \frac{3}{2} i

\frac{7}{4}

\frac{m}{9} = \frac{1}{7}

0 = x^{2} - 4 x - 32

2 - 7 x = 9

12 \cdot 6

What are the solutions to the equation 4=m^3+3 ?
The solutions to the equation 4=m^3+3 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i
Find the zeros of 4=m^3+3
The zeros of 4=m^3+3 are m=1,m=-1/2+(sqrt(3))/2 i,m=-1/2-(sqrt(3))/2 i