What is factor (x+4)^2-(y+1)^2 ?

The solution to factor (x+4)^2-(y+1)^2 is (x+5+y)(x-y+3)

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factor (x+4)^2-(y+1)^2

factor

(x + 4)^{2} - (y + 1)^{2}

(x + 5 + y) (x - y + 3)

Solution steps

(x + 4)^{2} - (y + 1)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x + 4)^{2} - (y + 1)^{2} = ((x + 4) + (y + 1)) ((x + 4) - (y + 1))

= ((x + 4) + (y + 1)) ((x + 4) - (y + 1))

Simplify

((x + 4) + (y + 1)) ((x + 4) - (y + 1)) : (x + 5 + y) (x - y + 3)

= (x + 5 + y) (x - y + 3)

32

(10 + 8 i) (- 5 + 6 i)

x^{2} + 2 \leq x^{2} + 5 x \leq x^{2} + 3

\frac{1}{3} \cdot 0

\frac{1}{\frac{1}{7}}

What is factor (x+4)^2-(y+1)^2 ?
The solution to factor (x+4)^2-(y+1)^2 is (x+5+y)(x-y+3)