What are the solutions to the equation 0=b^2+11b+30 ?

The solutions to the equation 0=b^2+11b+30 are b=-5,b=-6

Find the zeros of 0=b^2+11b+30

The zeros of 0=b^2+11b+30 are b=-5,b=-6

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0 = b^{2} + 11 b + 30

b = - 5, b = - 6

Solution steps

0 = b^{2} + 11 b + 30

Switch sides

b^{2} + 11 b + 30 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 30}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 30 = 1

b_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- 11 + 1}{2 \cdot 1}, b_{2} = \frac{- 11 - 1}{2 \cdot 1}

b = \frac{- 11 + 1}{2 \cdot 1} : - 5

b = \frac{- 11 - 1}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

b = - 5, b = - 6

\frac{( x - 2 )}{2 x + 1} < 3

x y + 2 x + 3 y + 6

(b^{2} + 3 b) + b + 3

- 2 y - 16 > 3 y + 24

i (2 - 7 i)^{2}

What are the solutions to the equation 0=b^2+11b+30 ?
The solutions to the equation 0=b^2+11b+30 are b=-5,b=-6
Find the zeros of 0=b^2+11b+30
The zeros of 0=b^2+11b+30 are b=-5,b=-6