What are the solutions to the equation x^2+9x+8=0 ?

The solutions to the equation x^2+9x+8=0 are x=-1,x=-8

Find the zeros of x^2+9x+8=0

The zeros of x^2+9x+8=0 are x=-1,x=-8

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x^{2} + 9 x + 8 = 0

x = - 1, x = - 8

Solution steps

x^{2} + 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 8 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 1}, x_{2} = \frac{- 9 - 7}{2 \cdot 1}

x = \frac{- 9 + 7}{2 \cdot 1} : - 1

x = \frac{- 9 - 7}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = - 1, x = - 8

x^{2} - 4 x = - 8

- 3 x + 22 < 16

4 t^{2} - 12 t + 9 - w^{2}

\frac{1 ^{4} + C}{1} = - 6

2 x^{2} - \frac{1}{6} x - 5

What are the solutions to the equation x^2+9x+8=0 ?
The solutions to the equation x^2+9x+8=0 are x=-1,x=-8
Find the zeros of x^2+9x+8=0
The zeros of x^2+9x+8=0 are x=-1,x=-8