What are the solutions to the equation 9n^2+6n=12 ?

The solutions to the equation 9n^2+6n=12 are n=(-1+sqrt(13))/3 ,n=-(1+sqrt(13))/3

Find the zeros of 9n^2+6n=12

The zeros of 9n^2+6n=12 are n=(-1+sqrt(13))/3 ,n=-(1+sqrt(13))/3

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9 n^{2} + 6 n = 12

n = \frac{- 1 + 13}{3}, n = - \frac{1 + 13}{3}

Decimal Notation

n = 0.86851 \dots, n = - 1.53518 \dots

Solution steps

9 n^{2} + 6 n = 12

Move

12

to the left side

9 n^{2} + 6 n - 12 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 12 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 12) = 613

n_{1, 2} = \frac{- 6 \pm 6 13}{2 \cdot 9}

Separate the solutions

n_{1} = \frac{- 6 + 6 13}{2 \cdot 9}, n_{2} = \frac{- 6 - 6 13}{2 \cdot 9}

n = \frac{- 6 + 6 13}{2 \cdot 9} : \frac{- 1 + 13}{3}

n = \frac{- 6 - 6 13}{2 \cdot 9} : - \frac{1 + 13}{3}

The solutions to the quadratic equation are:

n = \frac{- 1 + 13}{3}, n = - \frac{1 + 13}{3}

lo g_{4} (\frac{1}{16})

- 5 x = - 30

2 ∣ 1 - x ∣ - 4 = 2

- 10 x - 10 = - 10 x + 10

9 z^{2} + 6 z + 1

What are the solutions to the equation 9n^2+6n=12 ?
The solutions to the equation 9n^2+6n=12 are n=(-1+sqrt(13))/3 ,n=-(1+sqrt(13))/3
Find the zeros of 9n^2+6n=12
The zeros of 9n^2+6n=12 are n=(-1+sqrt(13))/3 ,n=-(1+sqrt(13))/3