What are the solutions to the equation 6x^2+6x+4=0 ?

The solutions to the equation 6x^2+6x+4=0 are x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6

Find the zeros of 6x^2+6x+4=0

The zeros of 6x^2+6x+4=0 are x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6

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6 x^{2} + 6 x + 4 = 0

x = - \frac{1}{2} + i \frac{15}{6}, x = - \frac{1}{2} - i \frac{15}{6}

Solution steps

6 x^{2} + 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 \cdot 4}{2 \cdot 6}

Simplify

6^{2} - 4 \cdot 6 \cdot 4 : 215 i

x_{1, 2} = \frac{- 6 \pm 2 15 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 2 15 i}{2 \cdot 6}, x_{2} = \frac{- 6 - 2 15 i}{2 \cdot 6}

x = \frac{- 6 + 2 15 i}{2 \cdot 6} : - \frac{1}{2} + i \frac{15}{6}

x = \frac{- 6 - 2 15 i}{2 \cdot 6} : - \frac{1}{2} - i \frac{15}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{15}{6}, x = - \frac{1}{2} - i \frac{15}{6}

x^{2} + 22 x + 120

\frac{1}{2} 72

2 x^{2} y^{3} + 3 x y^{2}

- 5 \leq - 4 x + 4 < 5

6 x^{2} = 8 x + 7

What are the solutions to the equation 6x^2+6x+4=0 ?
The solutions to the equation 6x^2+6x+4=0 are x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6
Find the zeros of 6x^2+6x+4=0
The zeros of 6x^2+6x+4=0 are x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6