What are the solutions to the equation 6x^2+13x+5=0 ?

The solutions to the equation 6x^2+13x+5=0 are x=-1/2 ,x=-5/3

Find the zeros of 6x^2+13x+5=0

The zeros of 6x^2+13x+5=0 are x=-1/2 ,x=-5/3

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6 x^{2} + 13 x + 5 = 0

x = - \frac{1}{2}, x = - \frac{5}{3}

Decimal Notation

x = - 0.5, x = - 1.66666 \dots

Solution steps

6 x^{2} + 13 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 6 \cdot 5}{2 \cdot 6}

1 3^{2} - 4 \cdot 6 \cdot 5 = 7

x_{1, 2} = \frac{- 13 \pm 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 13 + 7}{2 \cdot 6}, x_{2} = \frac{- 13 - 7}{2 \cdot 6}

x = \frac{- 13 + 7}{2 \cdot 6} : - \frac{1}{2}

x = \frac{- 13 - 7}{2 \cdot 6} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{5}{3}

4 π^{2} \cdot (\frac{0.67}{( 1.675 ) ^{2}})

25 x^{2} - 20 x y + 3 y^{2}

y^{3} - x y^{3}

158 = (\frac{217}{1.1}) (1 - e^{(- 0.1115207373)})

\frac{2 ( x + h ) ^{2} - 2 x ^{2}}{h}

What are the solutions to the equation 6x^2+13x+5=0 ?
The solutions to the equation 6x^2+13x+5=0 are x=-1/2 ,x=-5/3
Find the zeros of 6x^2+13x+5=0
The zeros of 6x^2+13x+5=0 are x=-1/2 ,x=-5/3