What is 33<3x-3((x-11)/2)<= 66 ?

The solution to 33<3x-3((x-11)/2)<= 66 is 11<x<= 33

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33<3x-3((x-11)/2)<= 66

33 < 3 x - 3 (\frac{x - 11}{2}) \leq 66

11 < x \leq 33

Interval Notation

(11, 33]

Solution steps

33 < 3 x - 3 (\frac{x - 11}{2}) \leq 66

a < u \leq b

then

a < u and u \leq b

33 < 3 x - 3 (\frac{x - 11}{2}) and 3 x - 3 (\frac{x - 11}{2}) \leq 66

33 < 3 x - 3 \cdot \frac{x - 11}{2} : x > 11

3 x - 3 \cdot \frac{x - 11}{2} \leq 66 : x \leq 33

Combine the intervals

x > 11 and x \leq 33

Merge Overlapping Intervals

11 < x \leq 33

4 x y - y^{2} + 4 x - y

\frac{2 a ^{3} - 2 a}{2 a}

- \frac{1}{2} + \frac{4}{5}

- 16 (x^{2} - 3 x - 4)

x^{2} - 12 x

What is 33<3x-3((x-11)/2)<= 66 ?
The solution to 33<3x-3((x-11)/2)<= 66 is 11<x<= 33