en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2+9x-5<= 0

Solution

2 x^{2} + 9 x - 5 \leq 0

Solution

- 5 \leq x \leq \frac{1}{2}

+2

Interval Notation

[- 5, \frac{1}{2}]

Decimal Notation

- 5 \leq x \leq 0.5

Solution steps

2 x^{2} + 9 x - 5 \leq 0

Factor

2 x^{2} + 9 x - 5 : (2 x - 1) (x + 5)

(2 x - 1) (x + 5) \leq 0

Identify the intervals

- 5 \leq x \leq \frac{1}{2}

Popular Examples

∣ x - 6 ∣ = x - 7

factor 50x^2-8 factor

50 x^{2} - 8

simplify sqrt((36x^4)/(25y^{10))}simplify

\frac{36 x ^{4}}{25 y ^{10}}

(γ - 4)^{2} = 64

factor 3x^2+20x-7 factor

3 x^{2} + 20 x - 7

Frequently Asked Questions (FAQ)

What is 2x^2+9x-5<= 0 ?
The solution to 2x^2+9x-5<= 0 is -5<= x<= 1/2