What are the solutions to the equation (a+1)^2=4 ?

The solutions to the equation (a+1)^2=4 are a=1,a=-3

Find the zeros of (a+1)^2=4

The zeros of (a+1)^2=4 are a=1,a=-3

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(a + 1)^{2} = 4

a = 1, a = - 3

Solution steps

(a + 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

a + 1 = 4 : a = 1

Solve

a + 1 = - 4 : a = - 3

The solutions to the quadratic equation are:

a = 1, a = - 3

4.5 + 0.75 d = 12

- 5 \cdot 4

lo g_{2} (8)

C (42) = \frac{( 42 ) ^{2}}{3025 - 55 ( 42 )}

\frac{y ^{2}}{5} = \frac{y + 10}{3}

What are the solutions to the equation (a+1)^2=4 ?
The solutions to the equation (a+1)^2=4 are a=1,a=-3
Find the zeros of (a+1)^2=4
The zeros of (a+1)^2=4 are a=1,a=-3