What is -2|q+2|>=-4 ?

The solution to -2|q+2|>=-4 is -4<= q<= 0

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-2|q+2|>=-4

- 2 ∣ q + 2 ∣ \geq - 4

- 4 \leq q \leq 0

Interval Notation

[- 4, 0]

Solution steps

- 2 ∣ q + 2 ∣ \geq - 4

Multiply both sides by

- 1

2 ∣ q + 2 ∣ \leq 4

Divide both sides by

2

∣ q + 2 ∣ \leq 2

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 2 \leq q + 2 \leq 2

q + 2 \geq - 2 and q + 2 \leq 2

q \geq - 4 and q \leq 0

Merge Overlapping Intervals

- 4 \leq q \leq 0

x^{2} - 16 x + 73 = 0

\frac{7}{10} + \frac{1}{5}

3 + \frac{4}{x} \geq \frac{x + 2}{x}

3 x^{3} - 5 x^{2} + 2 x

∣ 3 x - 1 ∣ < ∣ 2 + 2 x ∣