What are the solutions to the equation 2(x-7)^2-37=-35 ?

The solutions to the equation 2(x-7)^2-37=-35 are x=8,x=6

Find the zeros of 2(x-7)^2-37=-35

The zeros of 2(x-7)^2-37=-35 are x=8,x=6

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2 (x - 7)^{2} - 37 = - 35

x = 8, x = 6

Solution steps

2 (x - 7)^{2} - 37 = - 35

Move

37

to the right side

2 (x - 7)^{2} = 2

Divide both sides by

2

(x - 7)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 1 : x = 8

Solve

x - 7 = - 1 : x = 6

The solutions to the quadratic equation are:

x = 8, x = 6

2 b^{2} + 12 b - 24

\frac{4}{3} - \frac{1}{4}

2 x - 6 + 4 = 14

22 - 3 y > 7

\frac{x + 5}{2 x - 1} \leq 0

What are the solutions to the equation 2(x-7)^2-37=-35 ?
The solutions to the equation 2(x-7)^2-37=-35 are x=8,x=6
Find the zeros of 2(x-7)^2-37=-35
The zeros of 2(x-7)^2-37=-35 are x=8,x=6