What are the solutions to the equation s^2+13=0 ?

The solutions to the equation s^2+13=0 are s=sqrt(13)i,s=-sqrt(13)i

Find the zeros of s^2+13=0

The zeros of s^2+13=0 are s=sqrt(13)i,s=-sqrt(13)i

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s^{2} + 13 = 0

s = 13 i, s = - 13 i

Solution steps

s^{2} + 13 = 0

Move

13

to the right side

s^{2} = - 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = - 13, s = - - 13

- 13 = 13 i

- - 13 = - 13 i

s = 13 i, s = - 13 i

(3 y + 6)^{2} = 36

\frac{8 - 6 i}{3 i}

\frac{10}{3} + 4

25 x^{2} - 20 x + 3 = 0

87 - 6 x - 58 = 9 x - 1

What are the solutions to the equation s^2+13=0 ?
The solutions to the equation s^2+13=0 are s=sqrt(13)i,s=-sqrt(13)i
Find the zeros of s^2+13=0
The zeros of s^2+13=0 are s=sqrt(13)i,s=-sqrt(13)i