What is (2-3i)/(1-2i) ?

The solution to (2-3i)/(1-2i) is 8/5+1/5 i

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simplify (2-3i)/(1-2i)

simplify

\frac{2 - 3 i}{1 - 2 i}

\frac{8}{5} + \frac{1}{5} i

Solution steps

\frac{2 - 3 i}{1 - 2 i}

Multiply by the conjugate

\frac{1 + 2 i}{1 + 2 i}

= \frac{( 2 - 3 i ) ( 1 + 2 i )}{( 1 - 2 i ) ( 1 + 2 i )}

Simplify

\frac{( 2 - 3 i ) ( 1 + 2 i )}{( 1 - 2 i ) ( 1 + 2 i )} : \frac{8 + i}{5}

= \frac{8 + i}{5}

Rewrite in standard complex form:

\frac{8}{5} + \frac{1}{5} i

= \frac{8}{5} + \frac{1}{5} i

4 x^{2} + 9 x - 13 = 0

- 18 > 3 x

- \frac{π}{2} < x - \frac{π}{4} < \frac{π}{2}

\frac{x - 4 y}{5 x} - \frac{4 x}{3 x}

\frac{\frac{5}{6}}{4}