What are the solutions to the equation (x-5)(x+7)=0 ?

The solutions to the equation (x-5)(x+7)=0 are x=5,x=-7

Find the zeros of (x-5)(x+7)=0

The zeros of (x-5)(x+7)=0 are x=5,x=-7

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(x - 5) (x + 7) = 0

x = 5, x = - 7

Solution steps

(x - 5) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 7 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 7 = 0 : x = - 7

The solutions to the quadratic equation are:

x = 5, x = - 7

16 x^{3} - 250 y^{3}

3 x^{2} - 19 x + 6

- 3 (x - 2) < 8 or - 3 (x - 2) > 12

5 k - 8032 = 5 (2283.4) - 8032

- \frac{3}{5} - \frac{3}{5}

What are the solutions to the equation (x-5)(x+7)=0 ?
The solutions to the equation (x-5)(x+7)=0 are x=5,x=-7
Find the zeros of (x-5)(x+7)=0
The zeros of (x-5)(x+7)=0 are x=5,x=-7