What are the solutions to the equation 8x^2+8x-1=0 ?

The solutions to the equation 8x^2+8x-1=0 are x=(-2+sqrt(6))/4 ,x=-(2+sqrt(6))/4

Find the zeros of 8x^2+8x-1=0

The zeros of 8x^2+8x-1=0 are x=(-2+sqrt(6))/4 ,x=-(2+sqrt(6))/4

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8 x^{2} + 8 x - 1 = 0

x = \frac{- 2 + 6}{4}, x = - \frac{2 + 6}{4}

Decimal Notation

x = 0.11237 \dots, x = - 1.11237 \dots

Solution steps

8 x^{2} + 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

8^{2} - 4 \cdot 8 (- 1) = 46

x_{1, 2} = \frac{- 8 \pm 4 6}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 8 + 4 6}{2 \cdot 8}, x_{2} = \frac{- 8 - 4 6}{2 \cdot 8}

x = \frac{- 8 + 4 6}{2 \cdot 8} : \frac{- 2 + 6}{4}

x = \frac{- 8 - 4 6}{2 \cdot 8} : - \frac{2 + 6}{4}

The solutions to the quadratic equation are:

x = \frac{- 2 + 6}{4}, x = - \frac{2 + 6}{4}

3 (1 - 3 g) = - 7 + g

9 ab + 5 a^{2} b

4 x + 2 > 14 and - 21 x + 1 > 22

- (- 7)^{2}

\frac{2}{7} + \frac{3}{7} - \frac{1}{7}

What are the solutions to the equation 8x^2+8x-1=0 ?
The solutions to the equation 8x^2+8x-1=0 are x=(-2+sqrt(6))/4 ,x=-(2+sqrt(6))/4
Find the zeros of 8x^2+8x-1=0
The zeros of 8x^2+8x-1=0 are x=(-2+sqrt(6))/4 ,x=-(2+sqrt(6))/4